Evaluate: $\int\limits_{1}^{3} (x - 1)(x - 2)(x - 3) dx$ |
$\frac{8}{3}$ $\frac{7}{3}$ $0$ $1$ |
$0$ |
The correct answer is Option (3) → 0 ## Let $I = \int\limits_{1}^{3} (x - 1)(x - 2)(x - 3) dx$ $= \int\limits_{1}^{3} (x^{3} - 6x^{2} + 11x - 6) dx = \left[ \frac{x^{4}}{4} - \frac{6x^{3}}{3} + \frac{11x^{2}}{2} - 6x \right]_{1}^{3}$ $= \left[ \frac{81}{4} - \frac{162}{3} + \frac{99}{2} - 18 - \left( \frac{1}{4} - \frac{6}{3} + \frac{11}{2} - 6 \right) \right] = 0$ |