The value of $\frac{2 \sqrt{2}}{2-\sqrt{2}}$ is:
Answer & explanation
Correct answer: option 3
\frac{2 \sqrt{2}}{2-\sqrt{2}}
multiply and divide by ( 2 + √2 )
⇒ \frac{2 \sqrt{2}}{2-\sqrt{2}} × \frac{2 + \sqrt{2}}{2+ \sqrt{2}}
⇒ \frac{4 \sqrt{2} + 4 }{2}
= $2(\sqrt{2}+1)$