CUET Preparation Today
If 3sin θ + 4cos θ = 5 ; then find value of tan θ |
1 \(\frac{5}{3}\) \(\frac{3}{4}\) \(\sqrt {3}\) |
\(\frac{3}{4}\) |
3sin θ + 4cos θ = 5 ⇒ \(\frac{3}{5}\)sin θ + \(\frac{4}{5}\)cos θ = 1 .....(i) *(sin2θ + cos2θ = 1)* Therefore, from (i) sin θ = \(\frac{3}{5}\) & cos θ = \(\frac{4}{5}\) ⇒ tan θ = \(\frac{sin θ}{cos θ}\) = \(\frac{\frac{3}{5}}{\frac{4}{5}}\) = \(\frac{3}{4}\) |
