Study the following table and answer the question:
Number of students Appeared (A) and Passed (P) in an annual examination from four schools Q, R, S & T in five years (2014 to 2018)
|
School → |
Q |
R |
S |
T |
||||
|
Year ↓ |
A |
P |
A |
P |
A |
P |
A |
P |
|
2014 |
320 |
240 |
400 |
340 |
420 |
273 |
250 |
225 |
|
2015 |
400 |
320 |
380 |
285 |
350 |
280 |
300 |
228 |
|
2016 |
440 |
286 |
360 |
288 |
330 |
264 |
320 |
256 |
|
2017 |
350 |
252 |
420 |
294 |
380 |
247 |
350 |
315 |
|
2018 |
375 |
320 |
450 |
405 |
400 |
344 |
375 |
300 |
The total number of students passed from school S in 2014 and 2017 is what percent of 90% of the total number of students appeared from school T in 2015, 2016 and 2017? (correct to one decimal place)
Answer & explanation
Correct answer: option 3
Number of students passed from school S in 2014 and 2017 = 273 + 247 = 520
Number of students appeared from school T in 2015, 2016 and 2017 = 300 + 320 + 350 = 970
90% of Number of students appeared from school T in 2015, 2016 and 2017
= \(\frac{9}{10}\) × 970
= 873
Required percentage = \(\frac{520}{873}\) × 100
= 59.56%
= 59.6% (correct to one decimal place)