Match List I with List II
| List I | List II |
| (A) Liquation | (I) In |
| (B) Distillation | (II) Ni |
| (C) Zone refining | (III) Sn |
| (D) Mond Process | (IV) Zn |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → A-III, B-IV, C-I, D-II
(A) Liquation — This matches (III) Sn. A low-melting metal such as tin is made to flow off a sloping hearth, leaving the higher-melting impurities behind.
(B) Distillation — This matches (IV) Zn. Low-boiling metals such as zinc and mercury are evaporated and collected as the distillate.
(C) Zone refining — This matches (I) In. Impurities stay in the molten zone as a heater moves along the rod; it gives very pure Si, Ge, B, Ga and In.
(D) Mond Process — This matches (II) Ni. Nickel forms volatile nickel tetracarbonyl, which decomposes on stronger heating to pure nickel:
\( \ce{Ni + 4CO} \xrightarrow{\text{330-350 K}} \ce{Ni(CO)4} \xrightarrow{\text{450-470 K}} \ce{Ni + 4CO} \)
Note: This question is from the pre-rationalised NCERT book (2022-23). The topic is not there in the latest NCERT book (2026-27), and it is also out of the CUET 2026 syllabus.