CUET Preparation Today
CUET
General Test
General Ability
Letter Series
za_bx_a_bx_ay_x
yxazb
xzxyb
yzyab
yzyzb
There are 15 letters. If we break them in groups of 5 each. We will get like:
za_bx / _a_bx / _ay_x
zaybx / zaybx / zaybx
So, yzyzb