What is the value of $\frac{3cosec42^o}{

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

What is the value of $\frac{3cosec42^o}{sec48^o}-\frac{5cos32^o}{sin58^o}$

Options:

-1

-2

Correct Answer:

-2

Explanation:

$\frac{3 cosec42º}{sec48º}$ - $\frac{5 sec32º}{cosec58º}$

{ If A + B = 90º , Then secA = cosecB }

= $\frac{3 sec48º}{sec48º}$ - $\frac{5 sec32º}{sec32º}$

= 3 - 5

= -2