CUET Preparation Today
Radiation of frequency $2 v_0$ is incident on a metal with threshold frequency $v_0$. The correct statement of the following is _________. Fill in the blank with the correct answer from the options given below. |
No photoelectrons will be emitted All photoelectrons emitted will have kinetic energy equal to $h v_0$ Maximum kinetic energy of photoelectrons emitted can be $h v_0$ Maximum kinetic energy of photoelectrons emitted will be $2 h v_0$ |
Maximum kinetic energy of photoelectrons emitted can be $h v_0$ |
$ K.E_{max} = h\nu - \phi = 2h\nu_0 - h\nu_0 = h\nu_0$ The correct answer is Option (3) → Maximum kinetic energy of photoelectrons emitted can be $h v_0$ |
