Radiation of frequency $2 v_0$ is incident on a metal with threshold frequency $v_0$. The correct statement of the following is _________. Fill in the blank with the correct answer from the options given below. |
No photoelectrons will be emitted All photoelectrons emitted will have kinetic energy equal to $h v_0$ Maximum kinetic energy of photoelectrons emitted can be $h v_0$ Maximum kinetic energy of photoelectrons emitted will be $2 h v_0$ |
Maximum kinetic energy of photoelectrons emitted can be $h v_0$ |
The correct answer is Option (3) → Maximum kinetic energy of photoelectrons emitted can be $h v_0$ In the photoelectric effect, the maximum kinetic energy of emitted photoelectron is, $K_{max}=h(v-v_0)$ $v_0$ = Threshold frequency $v$ = frequency of incident light $K_{max} =h(2v_0-v_0)=hv_0$ |