Radiation of frequency $2 v_0$ is incident on a metal with threshold frequency $v_0$. The correct statement of the following is _________.
Fill in the blank with the correct answer from the options given below.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → Maximum kinetic energy of photoelectrons emitted can be $h v_0$
In the photoelectric effect, the maximum kinetic energy of emitted photoelectron is,
$K_{max}=h(v-v_0)$
$v_0$ = Threshold frequency
$v$ = frequency of incident light
$K_{max} =h(2v_0-v_0)=hv_0$