A conducting rod AB moves parallel to X-axis in a uniform magnetic field, pointing in the positive X-direction. The end A of the rod gets
Answer & explanation
Correct answer: option 1
According to right hand palm rule, the Lorentz force on free electrons $\vec{F} = q\vec{V} \times \vec{B}$ in the conductor will be directed towards end B. Hence, the end A gets positively charge.