Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Algebra

Question:

If $\begin{bmatrix}x+1 & 3 & 9\\-2 & 5 & 3\\0& 0 & z-3\end{bmatrix} = \begin{bmatrix}0 & 3 & 9\\-2 & y-5 & 3\\0& 0 & 10\end{bmatrix}$ then the values of x, y and z are :

Options:

$x=0, y=0, z=7 $

$x=-1, y=0, z=13 $

$x=0, y=10, z=7 $

$x=-1, y=10, z=13 $

Correct Answer:

$x=-1, y=10, z=13 $