If $\begin{bmatrix}x+1 & 3 & 9\\-2 & 5 & 3\\0& 0 & z-3\end{bmatrix} = \begin{bmatrix}0 & 3 & 9\\-2 & y-5 & 3\\0& 0 & 10\end{bmatrix}$ then the values of x, y and z are :

$x=-1, y=10, z=13 $

The correct answer is Option (4) → $x=-1, y=10, z=13 $

According to given relation between the given two matrices,

$x+1=0$   ....(1)

$y-5=5$    ....(2)

$z-3=10$    ....(3)

Solving (1), (2) and (3) we get,

$x=-1, y=10, z=13 $