If $\begin{bmatrix}x+1 & 3 & 9\\-2 & 5 & 3\\0& 0 & z-3\end{bmatrix} = \begin{bmatrix}0 & 3 & 9\\-2 & y-5 & 3\\0& 0 & 10\end{bmatrix}$ then the values of x, y and z are :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $x=-1, y=10, z=13 $
According to given relation between the given two matrices,
$x+1=0$ ....(1)
$y-5=5$ ....(2)
$z-3=10$ ....(3)
Solving (1), (2) and (3) we get,
$x=-1, y=10, z=13 $