If sin2θ = 2 sinθ - 1 . Then find the value of cosecθ .
Answer & explanation
Correct answer: option 1
sin2θ = 2 sinθ - 1
sinθ = 2 - \(\frac{1}{sinθ}\)
sinθ + \(\frac{1}{sinθ}\) = 2
sinθ = 1, then θ = 90°
cosecθ = cosec90° = 1
If sin2θ = 2 sinθ - 1 . Then find the value of cosecθ .
Correct answer: option 1
sin2θ = 2 sinθ - 1
sinθ = 2 - \(\frac{1}{sinθ}\)
sinθ + \(\frac{1}{sinθ}\) = 2
sinθ = 1, then θ = 90°
cosecθ = cosec90° = 1