Practicing Success
Practicing Success
CUET Preparation Today
If sin2θ = 2 sinθ - 1 . Then find the value of cosecθ . |
1 2 -1 0 |
1 |
sin2θ = 2 sinθ - 1 sinθ = 2 - \(\frac{1}{sinθ}\) sinθ + \(\frac{1}{sinθ}\) = 2 sinθ = 1, then θ = 90° cosecθ = cosec90° = 1 |
