CUET Preparation Today
If A and B are square symmetric matrices of the same order, then $AB'-B'A$ is: |
Symmetric Skew symmetric Scalar matrix Neither scalar nor square |
Skew symmetric |
The correct answer is Option (2) → Skew symmetric As A and B are symmetric matrix. $A^T=A$ and $B^T=B$ $(AB'-B'A)^T=(AB')^T-(B'A)^T$ $=BA^T-A^TB$ $=BA'-A'B$ $=B'A-AB'$ |
