An ideal gas is taken through  cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are Q₁ = 5960 J, Q₂ = -5585 J, Q₃ = -2980 J, Q₄ = 3645 J, respectively. The corresponding works involved are W₁ = 2200 J, W₂ = -825 J, W₃ = -1100 J and W₄, respectively. The value of W₄ is : 

765 J

\(\Delta Q = Q_1 + Q_2 + Q_3 + Q_4\)

\(\Delta Q = 5960 - 5585 - 2980 + 3645 \) = 1040 J

\(\Delta W = W_1 + W_2 + W_3 + W_4\)

\(\Delta W = 2200 - 825 - 1100 + W_4\) = 275 + W₄

For a cyclic process : U_f = U_i

\(\Delta U = U_f - U_i\) = 0

From First Law of Thermodynamics : \(\Delta Q = \Delta U + \Delta W\)

1040 + 0 = 275 + W₄ 

\(\Rightarrow W_4 = 765\) J