Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

Which of the following function is surjective but not injective?

Options:

$f:R→R, f (x) =x^4+2x^3-x^2+1$

$f:R→R, f (x) =x^3+x+1$

$f:R→R^+, f (x) =\sqrt{1+x^2}$

$f:R→R, f (x) =x^3+2x^2-x+1$

Correct Answer:

$f:R→R, f (x) =x^3+2x^2-x+1$

Explanation:

$f(x) =x^4+2x^3-x^2+1$ is polynomial of even degree hence its range can’t be R.

Hence not surjective.

$f(x) =x^3+x+1,f'(x)=3x^2+1$ ⇒ monotonic hence bijective.

$f(x) =\sqrt{1+x^2}$, neither surjective not injective.

$f(x) =x^3+2x^2-x+1,\,f'(x)=3x^2+4x-1⇒D=16+12>0$

Hence ( )x f is non-monotonic cubic polynomial hence surjective but not injective.