Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: D and F Block Elements

Question:

The pair of which salts are expected to have the same colour in their freshly prepared aqueous solutions.

Options:

\(VOCl_2, CuCl_2\)

\(CuCl_2, FeCl_2\)

\(FeCl_2, VOCl_2\)

\(MnCl_2, FeCl_2\)

Correct Answer:

\(VOCl_2, CuCl_2\)

Explanation:

The correct answer is option 1.  \(VOCl_2, CuCl_2\).

The color of a transition metal salt in aqueous solution is determined by the number of unpaired electrons in the metal ion. Both \(VOCl_2\) and \(CuCl_2\) contain a \(Cu^{2+}\) ion, which has one unpaired electron. This means that the two salts will have the same color in their freshly prepared aqueous solutions.

The other options are incorrect.

Option (2) \(CuCl_2\) and \(FeCl_2\) , is incorrect because \(FeCl_2\) has two unpaired electrons, while \(CuCl_2\) has only one unpaired electron.

Option (3) \(FeCl_2\) and \(VOCl_2\), is incorrect because \(FeCl_2\) has two unpaired electrons, while \(VOCl_2\) has only one unpaired electron.

Option (4), \(MnCl_2\) and \(FeCl_2\), is incorrect because \(MnCl_2\) has five unpaired electrons, while \(FeCl_2\) has only two unpaired electrons.