The perimeter of two squares are 44 cm and 24 cm. The perimeter of a third square, whose area is equal to difference of the area of these squares, is?
Answer & explanation
Correct answer: option 3
Perimeter of a square = 4 × side
side of square 1 = \(\frac{perimeter}{4}\)
= \(\frac{44}{4}\) = 11 cm
side of square 2 = \(\frac{24}{4}\) = 6 cm
Area of square 1 = (11)2 = 121 cm2
Area of square 2 = (6)2 = 36 cm2
Diff. = 121 - 36 = 85 cm2
area of square 3 = 85 cm2
side = \(\sqrt {85}\)
perimeter of square 3 = 4\(\sqrt {85}\)