CUET Preparation Today
If tanA - tanB - tanC = tanA tanB tanC, then find the value of A in terms of B and C. |
A = 2B - C A=\(\frac{B-C}{2}\) A = B + C A = 2C + B |
A = B + C |
Put B = 0 and satisfy the options. Given → tanA - 0 - tanC = 0 tanA = tanC So, take option C' A = 0 + C A = C satisfied. |
