The angle of elevation of the top of a tower height 50 m from a point 50√3 m from the foot of the tower on a horizontal plane?
Answer & explanation
Correct answer: option 1
AB = height of tower
Θ is angle of elevation
tan Θ AB : BC
50 : 50 \(\sqrt {3}\)
1 : \(\sqrt {3}\) ⇒ Θ = 30°