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The domain of the function $\cos^{-1}(2x-3)$ is |
[1, 2] [-1, 1] (1, 2) (-1, 1) |
[1, 2] |
The correct answer is Option (1) → [1, 2] Given: $f(x) = \cos^{-1}(2x - 3)$ Domain of $\cos^{-1}(u)$ is: $-1 \le u \le 1$ Apply this to $u = 2x - 3$: $-1 \le 2x - 3 \le 1$ Add 3 to all sides: $2 \le 2x \le 4$ Divide all sides by 2: $1 \le x \le 2$ |
