Akbar runs \(\frac{7}{2}\) times as fast as Birbal. In a race, if Akbar gives a lead of 80 meter to Birbal, find the distance from the starting point where both of them will meet:
Answer & explanation
Correct answer: option 2
Speed = \(\frac{Akbar}{Birbal}\) = \(\frac{7}{2}\)
Relative Speed in same direction = 7 - 2 = 5 m/sec
Meeting Time = \(\frac{Distance\;between\;them}{Relative\;speed}\)
= \(\frac{80}{5}\) = 16 seconds
Distance from the starting point = Distance covered by Akbar
⇒ 7 × 16 = 112 meter