Akbar runs \(\frac{7}{2}\) times as fast as Birbal. In a race, if Akbar gives a lead of 80 meter to Birbal, find the distance from the starting point where both of them will meet: |
120 meter 112 meter 100 meter 80 meter |
112 meter |
Speed = \(\frac{Akbar}{Birbal}\) = \(\frac{7}{2}\) Relative Speed in same direction = 7 - 2 = 5 m/sec Meeting Time = \(\frac{Distance\;between\;them}{Relative\;speed}\) = \(\frac{80}{5}\) = 16 seconds Distance from the starting point = Distance covered by Akbar ⇒ 7 × 16 = 112 meter |