How many 3s are there in the following sequence which are neither preceded by 6 nor immediately followed by 9?
93 66 39 59 37 89 16 39 63 9
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → Two
The digits are read as one continuous row: 9 3 6 6 3 9 5 9 3 7 8 9 1 6 3 9 6 3 9. A 3 counts only if the digit before it is not 6 and the digit after it is not 9. Taking each 3 in turn:
1st 3 (in 93): before it 9, after it 6 — counts
2nd 3 (in 39): before it 6 — does not count
3rd 3 (in 37): before it 9, after it 7 — counts
4th 3 (in 39): before it 6 — does not count
5th 3 (in 63): before it 6 — does not count
Two 3s meet the condition.