The probabilities of occurrence of two events E and F are 0.25 and 0.50 respectively. The probability of their simultaneous occurrence is 0.14. The probability that neither E nor F occurs is

0.39

The correct answer is Option (3) → 0.39 **

Given:

$P(E) = 0.25,\ P(F) = 0.50,\ P(E \cap F) = 0.14$

Probability that neither E nor F occurs:

$P(\overline{E \cup F}) = 1 - P(E \cup F)$

Now, $P(E \cup F) = P(E) + P(F) - P(E \cap F)$

$= 0.25 + 0.50 - 0.14 = 0.61$

Therefore,

$P(\overline{E \cup F}) = 1 - 0.61 = 0.39$

Final Answer:

$0.39$