CUET Preparation Today
CUET
-- Applied Mathematics - Section B2
Numbers, Quantification and Numerical Applications
The digit at the units place of $(101)^{101}+101!$ is :
1
3
7
9
The correct answer is Option (1) → 1
$(101)^{101}$ has unit digit 1.
$101!$ has unit digit 0.
Unit digit of $(101)^{101}+101!=1+0=1$
