If \( x \) is real, then the minimum value of \( x^2-8x+25 \) is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 9
By completing the square,
\( \displaystyle x^2-8x+25=(x-4)^2+9 \)
Since \( (x-4)^2\ge 0 \), the expression is least when x = 4, and its minimum value is 9.