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If $\frac{x^2-1}{x}= 8, $then what is the value of $\frac{x^6 -1}{x^3}= ?$ |
496 536 512 488 |
536 |
If x - \(\frac{1}{x}\) = n then, $x^3 - \frac{1}{x^3}$ = n3 + 3 × n $\frac{x^2-1}{x}$ = x - \(\frac{1}{x}\) = 8 what is the value of $\frac{x^6 -1}{x^3}= ?$ x3 - \(\frac{1}{x^3}\) = 83 + 3 × 8 x3 - \(\frac{1}{x^3}\) = 536 |
