If (x^2-1)/x= 8, then what is the value of (x^6 -1)/(x^3)= ?

If x - \(\frac{1}{x}\)  = n

then, $x^3 - \frac{1}{x^3}$ = n³ + 3 × n

 $\frac{x^2-1}{x}$ = x - \(\frac{1}{x}\) = 8

what is the value of $\frac{x^6 -1}{x^3}= ?$

x³ -  \(\frac{1}{x^3}\) = 8³ + 3 × 8

x³ -  \(\frac{1}{x^3}\) = 536