The function f(x)=x^3+1 is :

The correct answer is Option (1) → increasing in [2, 3]

$f(x)=x^3+1⇒f'(x)=3x^2⇒x=0$

$x$ → point of inflexion as for $x<0,f'(x)>0$

$x≥0,f'(x)>0$

⇒ increasing in R as $[2, 3] ∈ R$

increasing in [2, 3]