The value of [(\(\frac{sin A}{1 - cosA}\)) + (\(\frac{1 - cosA}{sinA}\))] ÷ (\(\frac{cot^2 A}{1+cosecA}\) + 1) is?

1 2 2\(\sqrt {2 }\) \(\frac{1}{2}\)

2

[(\(\frac{sin A}{1 - cosA}\)) + (\(\frac{1 - cosA}{sinA}\))] ÷ (\(\frac{cot^2 A}{1+cosecA}\) + 1) put A = 60° since value is same for all A) [(\(\frac{sin 60°}{1 - cos60°}\)) + (\(\frac{1 - cos60°}{sin60°}\)] ÷ (\(\frac{cot^2 60°}{1+cosec60°}\) + 1)