The value of [(\(\frac{sin A}{1 - cosA}\)) + (\(\frac{1 - cosA}{sinA}\))] ÷ (\(\frac{cot^2 A}{1+cosecA}\) + 1) is?
Answer & explanation
Correct answer: option 2
[(\(\frac{sin A}{1 - cosA}\)) + (\(\frac{1 - cosA}{sinA}\))] ÷ (\(\frac{cot^2 A}{1+cosecA}\) + 1)
put A = 60° since value is same for all A)
[(\(\frac{sin 60°}{1 - cos60°}\)) + (\(\frac{1 - cos60°}{sin60°}\)] ÷ (\(\frac{cot^2 60°}{1+cosec60°}\) + 1)
