Aryl Halides are less reactive towards nucleophilic substitution reactions because of

(A) Resonance Effect
(B) Stability of phenyl cation
(C) Presence of $sp^2$ Carbon attached to halogen
(D) Repulsion between benzene ring and incoming nucleophile

Choose the correct answer from the options given below:

(A), (B), (C) and (D)

The correct answer is Option (3) → (A), (B), (C) and (D)

Note: The given answer is as per NTA. However, there seems to be a mistake in the answer key. The correct answer should be Option 1- A, C and D as explained below:

Aryl halides are significantly less reactive than alkyl halides in nucleophilic substitution reactions due to several structural and electronic factors. Based on the chemical principles of haloarenes, the reasons include:

(A) Resonance Effect: In aryl halides (like chlorobenzene), the lone pair of electrons on the halogen atom is in conjugation with the $\pi$-electrons of the benzene ring. This delocalization creates a partial double bond character in the $C-X$ bond. A double bond is shorter and stronger than a single bond, making it much harder for a nucleophile to break.

(C) Presence of $sp^2$ Carbon: In aryl halides, the halogen is attached to an $sp^2$ hybridized carbon, whereas in alkyl halides, it is attached to an $sp^3$ hybridized carbon. An $sp^2$ carbon has more $s$-character (33%) than an $sp^3$ carbon (25%), making it more electronegative. This allows the carbon to hold the electron pair of the $C-X$ bond more tightly, resulting in a shorter, stronger bond that resists substitution.

(D) Repulsion: Benzene rings are electron-rich due to the delocalized $\pi$-electron cloud above and below the plane of the ring. Since nucleophiles are also electron-rich species, they experience electrostatic repulsion as they attempt to approach the electron-dense aromatic ring for an attack.

(B) Stability of Phenyl Cation : This is incorrect because nucleophilic substitution does not involve the formation of a phenyl cation; in fact, a phenyl cation would be highly unstable, not stable.

It seems there is some typo error in the NTA question. Instead of the word "instability", NTA has mentioned "stability" in Option2.