What is the LCM of the HCF of $\frac{2}{3},\frac{3}{4}$ and LCM of $\frac{5}{6},\frac{7}{8}$?
Answer & explanation
Correct answer: option 2
HCF of $\frac{2}{3},\frac{3}{4}$ = \(\frac{HCF \; of \;numerator }{LCM \; of \;denominator}\) = \(\frac{1}{12}\)
LCM of $\frac{5}{6},\frac{7}{8}$ = \(\frac{LCM \; of \;numerator }{HCF \; of \;denominator}\) = \(\frac{35}{2}\)
LCM of \(\frac{1}{12}\), \(\frac{35}{2}\) = \(\frac{LCM \; of \;numerator }{HCF \; of \;denominator}\) = \(\frac{35}{2}\)