What is the LCM of the HCF of $\frac{2}{3},\frac{3}{4}$ and LCM of $\frac{5}{6},\frac{7}{8}$?

$\frac{35}{2}$

HCF of $\frac{2}{3},\frac{3}{4}$ =  \(\frac{HCF \; of \;numerator }{LCM \; of \;denominator}\) = \(\frac{1}{12}\)

LCM of $\frac{5}{6},\frac{7}{8}$ = \(\frac{LCM \; of \;numerator }{HCF \; of \;denominator}\) = \(\frac{35}{2}\)

LCM of \(\frac{1}{12}\), \(\frac{35}{2}\) = \(\frac{LCM \; of \;numerator }{HCF \; of \;denominator}\) = \(\frac{35}{2}\)