Practicing Success
Practicing Success
CUET Preparation Today
The area of the region bounded by the curve \(y=x^{3}\) and the line \(y=4\) is |
\(\frac{32}{3}\) \(\frac{64}{3}\) \(\frac{256}{3}\) \(\frac{128}{3}\) |
\(\frac{32}{3}\) |
y → 0 y → 4 area of curve = $\int\limits_0^4y^{\frac{1}{3}}dy=\left[\frac{3y^{\frac{4}{3}}}{4}\right]_0^4$ $=3×4^{\frac{1}{3}}$ sq. units |
