The area of the region bounded by the curve \(y=x^{3}\) and the line \(y=4\) is
Answer & explanation
Correct answer: option 1
y → 0
y → 4
area of curve = $\int\limits_0^4y^{\frac{1}{3}}dy=\left[\frac{3y^{\frac{4}{3}}}{4}\right]_0^4$
$=3×4^{\frac{1}{3}}$ sq. units