Practicing Success
The equation of the curve through the origin satisfying the equation dy = (sec x + y tan x) dx is : |
y sin x = x y cos x = x y tan x = x none of these |
y cos x = x |
$\frac{d x}{d y}-y \tan x=\sec x$ I.F. = $e^{-\int \tan x d x}=\cos x$ $y \cos x=\int \sec x \cos x d x=x+c$ $y \cos x=x+c$ At (0, $\theta$), y cos x = x Since c = 0 Hence (2) is the correct answer. |