The graph shows the relationship between object distance (u) and image distance (v) for an equiconvex lens. The focal length of the lens is

0.5 cm 0.05 cm 5.00 cm 5.5 cm

5.00 cm

From the graph it can be extracted that for the given convex lens u = – 10 cm v = 10 cm ∴ \(\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \) \(\frac{1}{f} = \frac{1}{10} - \frac{1}{-10} \) ∴ f =  5 cm ∴ focal length = 5.00 cm