Let $f(x)=\frac{4^x}{4^x+2}$ Then $f(x)+f(1-x)$ is equal to

0 1 -1 None of these

1

$f(x)=\frac{4^x}{4^x+2}$ $f(1-x)=\frac{4^{1-x}}{4^{1-x}+2}=\frac{4/4^x}{4/4^x+2}=\frac{4}{4+2×4^x}$ $f(1-x)=\frac{2}{2+4x}$ so $f(x)+f(1-x)=\frac{4^x+2}{4^x+2}=1$