Consider the LPP: Minimize $Z = x + 2y$ subject to $2x + y ≥3,x + 2y ≥ 6, x, y ≥ 0$. The optimal feasible solution occurs at

Both (6, 0) and (0, 3)

The correct answer is Option (4) → Both (6, 0) and (0, 3)

Constraints

$2x+y\ge 3$

$x+2y\ge 6$

$x\ge 0,\;y\ge 0$

Corner points: $(0,3)$ and $(6,0)$

Compute $Z=x+2y$

$Z(0,3)=6$

$Z(6,0)=6$

The optimal feasible solutions occur at both $(0,3)$ and $(6,0)$.