Let $A=\begin{bmatrix} 0 & 2 & -5\\-2 & 0 & -7\\5 & 7 & 0 \end{bmatrix} $ and $B=\begin{bmatrix} 1 & 5 & 8 \\2 & 7 &4 \\3 & 9 & 10\end{bmatrix}$ then |AB|=
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 0
$A^T=-A$ ⇒ A is skew symmetric
so $|A^T|=-|A|$
$|A|=-|A|⇒|A|=0$
$|AB|=|A||B|=0$