CUET Preparation Today
If $y+\frac{1}{y}=3$, then what is the value of $\frac{1}{y^3}+y^3+2$? |
24 18 20 29 |
20 |
If $y+\frac{1}{y}=3$ what is the value of $\frac{1}{y^3}+y^3+2$ $\frac{1}{y^3}+y^3$ = (y + \(\frac{1}{y}\))3 - 3 $\frac{1}{y^3}+y^3$ = 33 - 3 = 18 $\frac{1}{y^3}+y^3+2$ = 18 + 2 = 20 |
