Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

Find the domain of the function $f(x) = \sin^{-1}\frac{x^2}{2}$

Options:

$[-\sqrt{2}, \sqrt{2}]$

$[-\sqrt{2}, 0]$

$[-1, \sqrt{2}]$

$[0, \sqrt{2}]$

Correct Answer:

$[-\sqrt{2}, \sqrt{2}]$

Explanation:

$f(x) = \sin^{-1}\frac{x^2}{2}$

We must have $0 ≤ \frac{x^2}{2}≤1$

$⇒0≤x^2≤2$

$⇒-\sqrt{2}≤x≤\sqrt{2}$

So, domain is $[-\sqrt{2}, \sqrt{2}]$