CUET Preparation Today
Find the domain of the function $f(x) = \sin^{-1}\frac{x^2}{2}$ |
$[-\sqrt{2}, \sqrt{2}]$ $[-\sqrt{2}, 0]$ $[-1, \sqrt{2}]$ $[0, \sqrt{2}]$ |
$[-\sqrt{2}, \sqrt{2}]$ |
$f(x) = \sin^{-1}\frac{x^2}{2}$ We must have $0 ≤ \frac{x^2}{2}≤1$ $⇒0≤x^2≤2$ $⇒-\sqrt{2}≤x≤\sqrt{2}$ So, domain is $[-\sqrt{2}, \sqrt{2}]$ |
