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If the area of a rhombus is 256 sq. cm and one of its diagonals is twice the other in length, then the length of smaller diagonal is? |
16 cm 18 cm 32 cm 36 cm |
16 cm |
area of the rhombus = \(\frac{1}{2}\) × d1 × d2 ⇒ 256 = \(\frac{1}{2}\) × d1 × 2d1 ⇒ (d1)2 = 256 ⇒ d1 = 16 cm |
