If the area of a rhombus is 256 sq. cm and one of its diagonals is twice the other in length, then the length of smaller diagonal is?
Answer & explanation
Correct answer: option 1
area of the rhombus = \(\frac{1}{2}\) × d1 × d2
⇒ 256 = \(\frac{1}{2}\) × d1 × 2d1
⇒ (d1)2 = 256
⇒ d1 = 16 cm