If the area of a rhombus is 256 sq. cm and one of its diagonals is twice the other in length, then the length of smaller diagonal is?

16 cm 18 cm 32 cm 36 cm

16 cm

area of the rhombus = \(\frac{1}{2}\) × d1 × d2 ⇒ 256 = \(\frac{1}{2}\) × d1 × 2d1 ⇒ (d1)2 = 256 ⇒ d1 = 16 cm