To measure a potential difference across a resistor of resistance R W a voltmeter of resistance Rv is used. To measure the potential with a minimum accuracy of 95 % then
Answer & explanation
Correct answer: option 4
$ \text{Let Initial current is I}$
$\text{After voltmeter was inserted the current through resistor R is } I'= I \frac{R_v}{R+R_v} \ge 0.95I$
$ \frac{R_v}{R+R_v} \ge 0.95 $
$ R_v \ge 0.95 R + 0.95 R_v$
$ \Rightarrow 0.05 R_v \ge 0.95R $
$ \Rightarrow R_v \ge 19R$