Find the general solution of the differential equation : y' = \(\frac{x+1}{2-y}\); y\(\neq \)2
Answer & explanation
Correct answer: option 3
\(\frac{dy}{dx}\) = \(\frac{x+1}{2-y}\)
dy.(2-y) = dx.(x+1) and then integrate to get :
x2 + y2 + 2x - 4y + C = 0