Practicing Success
Practicing Success
CUET Preparation Today
Find the general solution of the differential equation : y' = \(\frac{x+1}{2-y}\); y\(\neq \)2 |
x2 + y2 + 2x + 4y + C = 0 x2 + y2 + 4x + 2y + C = 0 x2 + y2 + 2x - 4y + C = 0 x2 + y2 + 4x - 2y + C = 0 |
x2 + y2 + 2x - 4y + C = 0 |
\(\frac{dy}{dx}\) = \(\frac{x+1}{2-y}\) dy.(2-y) = dx.(x+1) and then integrate to get : x2 + y2 + 2x - 4y + C = 0 |
