CUET Preparation Today
CUET
Physics
Semiconductors and Electronic Devices
a
b
c
d
$\text{Current Gain is}\alpha = \frac{\Delta I_C}{\Delta I_E} = 0.96$
$ \Delta I_C = 0.96\times 7.2mA = 6.91 mA$
$ \Delta I_B = 7.20 mA - 6.91 mA = 0.29 mA$
