CUET Preparation Today
Integrating factor of the differential equation $\cos x \frac{d y}{d x}+y \sin x=1$ is : |
cos x tan x sec x sin x |
sec x |
$\frac{d y}{d x}+y \frac{\sin x}{\cos x}=\frac{1}{\cos x}$ Here P = tan x, Q = sec x ∴ I. F. = $e^{\int \tan x d x}=e^{\log \sec x}=\sec x$ Hence (3) is the correct answer. |
