CUET Preparation Today
If 9 tan2θ - 3 = 0, find the value of 3sinθ + cos(θ) . |
1 \(\frac{2 + √3}{2}\) \(\frac{4 + √3}{2}\) \(\frac{3 + √3}{2}\) |
\(\frac{3 + √3}{2}\) |
9 tan2α - 3 = 0 tan2α = \(\frac{3}{9}\) = \(\frac{1}{3}\) tanθ = \(\frac{1}{\sqrt {3}}\) θ = 30° Now, ⇒ 3sinθ + cos(θ) = 3 × \(\frac{1}{2}\) + cos(30°) = \(\frac{3}{2}\) + \(\frac{√3}{2}\) = \(\frac{3 + √3}{2}\) |
