A and B are mutually exclusive events with \(P(A)=\frac{1}{4}\) and \(P(B)=\frac{2}{5}\). What is the probability that A or B occurs?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \(\frac{13}{20}\)
Mutually exclusive events cannot occur together, so P(A and B) \(=0\) and P(A or B) = P(A) + P(B).
P(A or B) \(\displaystyle =\frac{1}{4}+\frac{2}{5}=\frac{5}{20}+\frac{8}{20}=\frac{13}{20}\)