Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?
Answer & explanation
Correct answer: option 4
Let the present age of man be M years and his son be S years.
According to the question:
M - 4 = 6 (S - 4)
M - 4 = 6S - 24
M = 6S - 20 ------1st equation
M + 16 = 2(S + 16)
M + 16 = 2S + 32 -------2nd equation
Putting (1) in the (2) equation
6S - 20 + 16 = 2S + 32
4S = 36
S = 9
M = 6S - 20 i.e. 54 - 20 = 34
So, the age of son is 9 years, and the age of father is 34 years