If $C$ is the original value of the asset, $S$ is the scrap value, $n$ is the useful life of the asset and $D$ is the annual depreciation, then |
$D=\frac{C+S}{n}$ $D=\frac{C-n}{S}$ $D=n\frac{C}{S}$ $D=\frac{C-S}{n}$ |
$D=\frac{C-S}{n}$ |
The correct answer is Option (4) → $D=\frac{C-S}{n}$ Using the linear (straight-line) depreciation method: Annual depreciation: $D = \frac{C - S}{n}$ Where:
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