The sides of an equilateral triangle are increasing at the rate of 5 cm/sec. The rate at which the area increases when the side is 20 cm, is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(50\sqrt{3}\,\mathrm{cm^2/sec}\)
Let a be the side. The area of an equilateral triangle is
\( \displaystyle A = \frac{\sqrt{3}}{4}a^2 \)
Differentiating with respect to time t (chain rule):
\( \displaystyle \frac{dA}{dt} = \frac{\sqrt{3}}{4}\cdot 2a\,\frac{da}{dt} \)
\( \displaystyle = \frac{\sqrt{3}}{2}\,a\,\frac{da}{dt} \)
Putting \(a = 20\) and \(\frac{da}{dt} = 5\):
\( \displaystyle \frac{dA}{dt} = \frac{\sqrt{3}}{2}\times 20 \times 5 \)
\(= 50\sqrt{3}\,\mathrm{cm^2/sec}\)