The height of a trapezium is 68 cm, and the sum of its parallel sides is 75 cm. If the area of the trapezium is $\frac{6}{17}$ times of the area of a square, then the length of the diagonal of the square is: (Take $\sqrt{2}$ = 1.41) |
127.39 cm 183.49 cm 119.85 cm 102.39 cm |
119.85 cm |