The number of all possible non-zero matrices of order $3×4$ with each entry 0 or 1 or 2 is : |
$3^{12}+1$ $3^{12}+3$ $3^{12}$ $3^{12}-1$ |
$3^{12}-1$ |
The correct answer is Option (4) → $3^{12}-1$ A matrix of order 3 × 4 has 12 elements. Each entry can take on any of the 3 values. ∴ Total no of matrices = $3^{12}$ However, in this case one of the matrix will be null matrix of order 3 × 4. $∴ 3^{12}-1$ |