Case : Read the passage and answer the question(s).

When light is incident at polarizing angle at the interface of a refracting medium the refractive index of the medium is equal to the tangent of the polarizing angle. The angle of incidence of light, at which when ordinary light is incident on transparent refracting medium, the reflected light becomes maximum rich in plane polarized light is called polarizing angle.

What is the polarizing angle for a air-water interface? (Hint : μ = \(\frac{4}{3}\))

\(\tan^{-1} {4/3}\)

Use : 

$ \mu= tan\theta_p$

$ \theta_p = tan^{-1}\mu = tan^{-1}(\frac{4}{3})$

θ_p : polarizing angle